Q. The collar A in Figure slides along the rotating rod OB. The angular position of the rod is given by π =2/3 *(ππ‘)Β² rad and the distance of the collar from O varies as r =18tβ΄+4 m, where time t is measured in seconds. Determine the velocity and acceleration vectors of the collar at t =0.4 s. Solution :- Given polar co-ordinates are r = 18tβ΄+4 and π =2/3 Γ(ππ‘)Β² r`= 72tΒ³ π` =4/3 Γ(ππ‘) r``= 216tΒ² π`` =4/3 Γ(π) At t=0.4 sec r = 18(0.4)β΄+4 = 4.46m r`= 72(0.4)Β³ = 4.608 m/a r``= 216(0.4)Β² = 34.56 m/sΒ² π = 2Γ(3.14Γ0.4)Β²/3 =0.335 rad π`= 4Γ3.14Γ0.4/3 = 1.675 rad/se...
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